A husband and wife both have normal vision,al | vedclass

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(A) Colorblindness is an $X$-linked recessive disorder.Let $X^C$ be the allele for colorblindness and $X$ be the allele for normal vision.The husband

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(A) Colorblindness is an $X$-linked recessive disorder.Let $X^C$ be the allele for colorblindness and $X$ be the allele for normal vision.The husband has normal vision,so his genotype is $XY$.The wife has normal vision,but since her father was colorblind,she must be a carrier,so her genotype is $XX^C$.When we cross $XY 	imes XX^C$,the possible genotypes for their children are:$1. XX$ (Normal daughter)$2. XX^C$ (Carrier daughter)$3. XY$ (Normal son)$4. X^CY$ (Colorblind son)Since colorblindness is $X$-linked recessive,a daughter can only be colorblind if she inherits the $X^C$ allele from both parents. In this case,the father is normal $(XY)$,so he cannot pass the $X^C$ allele to his daughter.Therefore,the probability of their daughter being colorblind is $0\%$.

$A$ husband and wife both have normal vision,although both of their fathers were colorblind. What is the probability that their daughter will be colorblind (in $\%$)?

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