$\int \left(1+x-\frac{1}{x}\right) e^{x+\frac{1}{x}} ~d x$ is equal to

  • A
    $(x-1) e^{x+\frac{1}{x}}+c$,where $c$ is a constant of integration.
  • B
    $x e^{x+\frac{1}{x}}+c$,where $c$ is a constant of integration.
  • C
    $(x+1) e^{x+\frac{1}{x}}+c$,where $c$ is a constant of integration.
  • D
    $-x e^{x+\frac{1}{x}}+c$,where $c$ is a constant of integration.

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