$A$ ball is projected at an angle of $45^{\circ}$ with the horizontal. It passes through a wall of height $h$ at a horizontal distance $d_1$ from the point of projection and strikes the ground at a distance $d_1+d_2$ from the point of projection. Then $h$ is:

  • A
    $h=\frac{2 d_1 d_2}{d_1+d_2}$
  • B
    $h=\frac{d_1 d_2}{d_1+d_2}$
  • C
    $h=\frac{\sqrt{2} d_1 d_2}{d_1+d_2}$
  • D
    $h=\frac{d_1 d_2}{2(d_1+d_2)}$

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