$\mathop {\lim }\limits_{x \to 1} \frac{(2x - 3)(\sqrt{x} - 1)}{2x^2 + x - 3} = $

$\mathop {\lim }\limits_{x \to 2} \frac{|x - 2|}{x - 2} = $

$\mathop {\lim }\limits_{x \to 0} \frac{{\tan x - \sin x}}{{{x^3}}} = $

$\lim _{x}$ ${\rightarrow 1} \frac{(1-x)(1-x^2) \cdots (1-x^{2n})}{\{(1-x)(1-x^2) \cdots (1-x^n)\}^2} = \dots, \forall n \in N$

$\mathop {\lim }\limits_{x \to \infty } \frac{{(x - 1)(2x + 3)}}{{{x^2}}} = $

यदि $f(x) = \begin{cases} x & \text{यदि } x < 0 \\ 1 & \text{यदि } x = 0 \\ x^2 & \text{यदि } x > 0 \end{cases}$ है,तो $\mathop {\lim }\limits_{x \to 0} f(x) = $