$\mathop {\lim }\limits_{x \to \infty } \frac{{3{x^2} + 2x - 1}}{{2{x^2} - 3x - 3}} = $

  • A
    $1$
  • B
    $3$
  • C
    $\frac{3}{2}$
  • D
    $-\frac{3}{2}$

Explore More

Similar Questions

જો $f(x) = \begin{cases} \frac{\sin[x]}{[x]}, & [x] \neq 0 \\ 0, & [x] = 0 \end{cases}$ જ્યાં $[x]$ એ $x$ થી નાનો અથવા તેના જેટલો મહત્તમ પૂર્ણાંક દર્શાવે છે,તો $\lim_{x \to 0^-} f(x)$ શું થાય?

લક્ષની કિંમત શોધો: $\mathop {\lim }\limits_{x \to 3} (x+3)$

$\lim _{x \rightarrow 0} \frac{\cos (\sin x)-\cos x}{x^{4}}$ ની કિંમત શોધો.

$\mathop {\lim }\limits_{x \to \infty } \left( {\left| {{x^2}} \right| + x} \right)\log \left( {x{{\cot }^{ - 1}}x} \right)$ ની કિંમત શોધો.

$\lim _{x \rightarrow-\infty} \frac{3|x|-x}{|x|-2 x} - \lim _{x \rightarrow 0} \frac{\log (1+x^3)}{\sin ^3 x} =$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo