For a common emitter amplifier,the voltage gain is $50$,the input resistance is $200 \ \Omega$,and the output resistance is $400 \ \Omega$. The power gain of the amplifier will be:

In a $CE$ transistor, a change of $8.0 \,mA$ in the emitter current produces a change of $7.8 \,mA$ in the collector current. What change in the base current is necessary to produce the same change in the collector current (in $\mu A$)?

In the given circuit,a transistor with a current gain $\beta = 100$ is used. To have $V_{CE} = 5 \text{ V}$ and $V_{BE} = 0$,what should be the value of the base resistance $R_b$?

For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relation between $\alpha$ and $\beta$ is

The current gain for a common emitter amplifier is $69$. If the emitter current is $7 \ mA$,the base current is......$mA$

For a transistor,$\alpha_{dc}$ and $\beta_{dc}$ are the current ratios,then the value of $\frac{\beta_{dc}-\alpha_{dc}}{\alpha_{dc} \times \beta_{dc}}$ is: