A pre-weighed vessel is filled with O_2 and w | vedclass

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(C) According to Avogadro's Law,at constant temperature and pressure,equal volumes of gases contain an equal number of moles.Since the volume of the v

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Half the weight of $SO_2$.

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(C) According to Avogadro's Law,at constant temperature and pressure,equal volumes of gases contain an equal number of moles.Since the volume of the vessel is constant,$n_{O_2} = n_{SO_2}$.We know that $n = \frac{w}{M}$,where $w$ is the weight and $M$ is the molar mass.Therefore,$\frac{w_{O_2}}{M_{O_2}} = \frac{w_{SO_2}}{M_{SO_2}}$.The molar mass of $O_2$ is $32 \ g/mol$ and the molar mass of $SO_2$ is $64 \ g/mol$.Substituting the values: $\frac{w_{O_2}}{32} = \frac{w_{SO_2}}{64}$.$w_{O_2} = w_{SO_2} 	imes \frac{32}{64} = \frac{1}{2} 	imes w_{SO_2}$.Thus,the weight of $O_2$ is half the weight of $SO_2$.

$A$ pre-weighed vessel is filled with $O_2$ and weighed at $STP$. It is then evacuated and filled with $SO_2$ gas at the same temperature and pressure,and weighed again. The weight of $O_2$ will be:

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