What is the equation of the directrix of the parabola $y^2 + 4y + 4x + 2 = 0$?
- A$x = -1$
- B$x = 1$
- C$x = -\frac{3}{2}$
- D$x = \frac{3}{2}$
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View SolutionIf the directrix of the parabola $x^2+4y-6x+\lambda=0$ is $y+1=0$,then which of the following is correct?
Match the items of List-$I$ with those of List-$II$. Then,which of the following is correct?
List-$I$ List-$II$ $A$. Equation of the tangent drawn at $(2, \sqrt{8})$ on the curve $y^2 = 4x$ is $(i) -36$ $B$. Equation of the normal to the curve $y^2 = 16x$,that makes an angle of $45^{\circ}$ with its axis is $(ii) 4$ $C$. The chord joining the points $(x_1, y_1)$ and $(x_2, y_2)$ on the curve $y^2 = 12x$ is a focal chord if $y_1 y_2 =$ $(iii) 8$ $D$. $A$ value of $k$ for which $x - 3 = 0$ is the directrix of the curve $y^2 - kx + 16 = 0$ is $(iv) x - \sqrt{2}y + 2 = 0$ $(v) x + y - 12 = 0$ $(vi) x - y - 12 = 0$
| List-$I$ | List-$II$ |
| $A$. Equation of the tangent drawn at $(2, \sqrt{8})$ on the curve $y^2 = 4x$ is | $(i) -36$ |
| $B$. Equation of the normal to the curve $y^2 = 16x$,that makes an angle of $45^{\circ}$ with its axis is | $(ii) 4$ |
| $C$. The chord joining the points $(x_1, y_1)$ and $(x_2, y_2)$ on the curve $y^2 = 12x$ is a focal chord if $y_1 y_2 =$ | $(iii) 8$ |
| $D$. $A$ value of $k$ for which $x - 3 = 0$ is the directrix of the curve $y^2 - kx + 16 = 0$ is | $(iv) x - \sqrt{2}y + 2 = 0$ |
| $(v) x + y - 12 = 0$ | |
| $(vi) x - y - 12 = 0$ |
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