frac{3sqrt{2}}{sqrt{6} + sqrt{3}} - frac{4sqr | vedclass

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(D) प्रत्येक पद का परिमेयकरण करने पर:प्रथम पद: $\frac{3\sqrt{2}}{\sqrt{6} + \sqrt{3}} = \frac{3\sqrt{2}(\sqrt{6} - \sqrt{3})}{6 - 3} = 2\sqrt{3} - \sq

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(D) प्रत्येक पद का परिमेयकरण करने पर:प्रथम पद: $\frac{3\sqrt{2}}{\sqrt{6} + \sqrt{3}} = \frac{3\sqrt{2}(\sqrt{6} - \sqrt{3})}{6 - 3} = 2\sqrt{3} - \sqrt{6}$द्वितीय पद: $\frac{4\sqrt{3}}{\sqrt{6} + \sqrt{2}} = \frac{4\sqrt{3}(\sqrt{6} - \sqrt{2})}{6 - 2} = 3\sqrt{2} - \sqrt{6}$तृतीय पद: $\frac{\sqrt{6}}{\sqrt{3} + \sqrt{2}} = \frac{\sqrt{6}(\sqrt{3} - \sqrt{2})}{3 - 2} = 3\sqrt{2} - 2\sqrt{3}$सभी पदों को जोड़ने पर:$(2\sqrt{3} - \sqrt{6}) - (3\sqrt{2} - \sqrt{6}) + (3\sqrt{2} - 2\sqrt{3}) = 0$

$\frac{3\sqrt{2}}{\sqrt{6} + \sqrt{3}} - \frac{4\sqrt{3}}{\sqrt{6} + \sqrt{2}} + \frac{\sqrt{6}}{\sqrt{3} + \sqrt{2}} = $

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