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(B) $1$. First,find the image formed by the curved silvered surface (acting as a concave mirror).The radius of curvature $R = 10\, cm$. The focal leng

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$20\, cm$ below flat surface

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(B) $1$. First,find the image formed by the curved silvered surface (acting as a concave mirror).The radius of curvature $R = 10\, cm$. The focal length $f = -R/2 = -5\, cm$.The object distance $u$ from the pole of the mirror is $u = -(R - 6) = -(10 - 6) = -4\, cm$.Using the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$:$\frac{1}{v} + \frac{1}{-4} = \frac{1}{-5} \Rightarrow \frac{1}{v} = \frac{1}{4} - \frac{1}{5} = \frac{1}{20}$.Thus,$v = 20\, cm$ from the pole of the mirror (inside the glass).$2$. Now,find the apparent position of this image as seen from outside the flat surface.The image formed by the mirror is at a distance of $20\, cm$ from the pole. Since the bubble was $6\, cm$ from the flat surface,the image is at a distance of $20\, cm$ from the curved surface. The total depth from the flat surface is $10\, cm + 20\, cm = 30\, cm$.Using the apparent depth formula $d_{apparent} = d_{real} / \mu$:$d_{apparent} = 30 / 1.5 = 20\, cm$.Therefore,the image is seen $20\, cm$ below the flat surface.

$A$ hemispherical glass body of radius $10\, cm$ and refractive index $1.5$ is silvered on its curved surface. $A$ small air bubble is $6\, cm$ below the flat surface inside it along the axis. The position of the image of the air bubble made by the mirror is seen:

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