$A$ life insurance agent found the following data for the distribution of ages of $100$ policy holders. Calculate the median age,if policies are given only to persons having age $18$ years onwards but less than $60$ years.
Age (in years) Number of policy holders Below $20$ $2$ Below $25$ $6$ Below $30$ $24$ Below $35$ $45$ Below $40$ $78$ Below $45$ $89$ Below $50$ $92$ Below $55$ $98$ Below $60$ $100$
| Age (in years) | Number of policy holders |
| Below $20$ | $2$ |
| Below $25$ | $6$ |
| Below $30$ | $24$ |
| Below $35$ | $45$ |
| Below $40$ | $78$ |
| Below $45$ | $89$ |
| Below $50$ | $92$ |
| Below $55$ | $98$ |
| Below $60$ | $100$ |
- A$35$
- B$35.76$
- C$25.56$
- D$35.33$
Explore More
Similar Questions
The following table gives the production yield per hectare of wheat of $100$ farms of a village.
Production yield (in kg/ha) Number of farms $50-55$ $2$ $55-60$ $8$ $60-65$ $12$ $65-70$ $24$ $70-75$ $38$ $75-80$ $16$
Change the distribution to a 'more than type' distribution,and draw its ogive.
| Production yield (in kg/ha) | Number of farms |
|---|---|
| $50-55$ | $2$ |
| $55-60$ | $8$ |
| $60-65$ | $12$ |
| $65-70$ | $24$ |
| $70-75$ | $38$ |
| $75-80$ | $16$ |
Change the distribution to a 'more than type' distribution,and draw its ogive.
Medium
View Solution$A$ survey was conducted by a group of students as a part of their environment awareness programme,in which they collected the following data regarding the number of plants in $20$ houses in a locality. Find the mean number of plants per house.
Number of plants $0-2$ $2-4$ $4-6$ $6-8$ $8-10$ $10-12$ $12-14$ Number of houses $1$ $2$ $1$ $5$ $6$ $2$ $3$
Which method did you use for finding the mean,and why?
| Number of plants | $0-2$ | $2-4$ | $4-6$ | $6-8$ | $8-10$ | $10-12$ | $12-14$ |
| Number of houses | $1$ | $2$ | $1$ | $5$ | $6$ | $2$ | $3$ |
Which method did you use for finding the mean,and why?
Medium
View SolutionConsider the following distribution of daily wages of $50$ workers of a factory.
$\begin{array}{|l|c|c|c|c|c|} \hline \text{Daily wages (in Rs.)} & 100-120 & 120-140 & 140-160 & 160-180 & 180-200 \\ \hline \text{Number of workers} & 12 & 14 & 8 & 6 & 10 \\ \hline \end{array}$
Find the mean daily wages of the workers of the factory by using an appropriate method.
$\begin{array}{|l|c|c|c|c|c|} \hline \text{Daily wages (in Rs.)} & 100-120 & 120-140 & 140-160 & 160-180 & 180-200 \\ \hline \text{Number of workers} & 12 & 14 & 8 & 6 & 10 \\ \hline \end{array}$
Find the mean daily wages of the workers of the factory by using an appropriate method.
Medium
View SolutionThe distribution below shows the number of wickets taken by bowlers in one-day cricket matches. Find the mean number of wickets by choosing a suitable method. What does the mean signify?
Number of wickets $20$-$60$ $60$-$100$ $100$-$150$ $150$-$250$ $250$-$350$ $350$-$450$ Number of bowlers $7$ $5$ $16$ $12$ $2$ $3$
| Number of wickets | $20$-$60$ | $60$-$100$ | $100$-$150$ | $150$-$250$ | $250$-$350$ | $350$-$450$ |
| Number of bowlers | $7$ | $5$ | $16$ | $12$ | $2$ | $3$ |
Medium
View SolutionThe following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is $Rs. 18$. Find the missing frequency $f$.
Daily pocket allowance (in $Rs.$) $11-13$ $13-15$ $15-17$ $17-19$ $19-21$ $21-23$ $23-25$ Number of children $7$ $6$ $9$ $13$ $f$ $5$ $4$
| Daily pocket allowance (in $Rs.$) | $11-13$ | $13-15$ | $15-17$ | $17-19$ | $19-21$ | $21-23$ | $23-25$ |
| Number of children | $7$ | $6$ | $9$ | $13$ | $f$ | $5$ | $4$ |
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo