A light inextensible string that goes over a | vedclass

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(C) Let $m_1 = 0.36 	ext{ kg}$ and $m_2 = 0.72 	ext{ kg}$.For the block of mass $m_2$,the equation of motion is: $m_2 g - T = m_2 a$.For the block o

Vedclass · Accepted Answer

$8$

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(C) Let $m_1 = 0.36 	ext{ kg}$ and $m_2 = 0.72 	ext{ kg}$.For the block of mass $m_2$,the equation of motion is: $m_2 g - T = m_2 a$.For the block of mass $m_1$,the equation of motion is: $T - m_1 g = m_1 a$.Adding these two equations: $(m_2 - m_1) g = (m_1 + m_2) a$.$a = \frac{(m_2 - m_1) g}{m_1 + m_2} = \frac{(0.72 - 0.36) 	imes 10}{0.72 + 0.36} = \frac{0.36 	imes 10}{1.08} = \frac{3.6}{1.08} = \frac{10}{3} 	ext{ m/s}^2$.The tension $T$ is given by: $T = m_1(g + a) = 0.36 	imes (10 + \frac{10}{3}) = 0.36 	imes \frac{40}{3} = 0.12 	imes 40 = 4.8 	ext{ N}$.The displacement $s$ in $t = 1 	ext{ s}$ starting from rest is: $s = \frac{1}{2} a t^2 = \frac{1}{2} 	imes \frac{10}{3} 	imes (1)^2 = \frac{5}{3} 	ext{ m}$.The work done by the string on the block of mass $m_1$ is: $W = T 	imes s = 4.8 	imes \frac{5}{3} = 1.6 	imes 5 = 8 	ext{ J}$.

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