A wire which when bent in the form of a squar | vedclass

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(C) Area of the square $= 484 \, cm^2$.Let the side of the square be $a$. Then $a^2 = 484$,which gives $a = \sqrt{484} = 22 \, cm$.The perimeter of th

Vedclass · Accepted Answer

$616$

Vedclass · Answer

(C) Area of the square $= 484 \, cm^2$.Let the side of the square be $a$. Then $a^2 = 484$,which gives $a = \sqrt{484} = 22 \, cm$.The perimeter of the square $= 4 	imes a = 4 	imes 22 = 88 \, cm$.When the same wire is bent into a circle,the circumference of the circle equals the perimeter of the square.Circumference $= 2\pi r = 88 \, cm$.$2 	imes \frac{22}{7} 	imes r = 88$.$r = \frac{88 	imes 7}{44} = 14 \, cm$.The area of the circle $= \pi r^2 = \frac{22}{7} 	imes 14 	imes 14$.Area $= 22 	imes 2 	imes 14 = 616 \, cm^2$.

$A$ wire which when bent in the form of a square encloses an area of $484 \, cm^2$. What will be the enclosed area when the same wire is bent into the form of a circle? (in $cm^2$)

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