An octahedral complex of Co^{3+} is diamagnet | vedclass

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Question

(C) The atomic number of $Co$ is $27$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since the complex is octahedral and diamagnetic,the li

Vedclass · Accepted Answer

$d^2sp^3$

Vedclass · Answer

(C) The atomic number of $Co$ is $27$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since the complex is octahedral and diamagnetic,the ligands must be strong field ligands that cause pairing of electrons in the $3d$ orbitals.This results in two empty $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals,which hybridize to form six $d^2sp^3$ hybrid orbitals.Thus,the hybridisation involved is $d^2sp^3$.

List-$I$ (Molecules/ion)	List-$II$ (Hybridisation of central atom)
$A. PF_5$	$I. dsp^2$
$B. SF_6$	$II. sp^3d$
$C. Ni(CO)_4$	$III. sp^3d^2$
$D. [PtCl_4]^{2-}$	$IV. sp^3$

An octahedral complex of $Co^{3+}$ is diamagnetic. The hybridisation involved in the formation of the complex is

Similar Questions

Match the List-$I$ with List-$II$
List-$I$ (Molecules/ion) List-$II$ (Hybridisation of central atom)
$A. PF_5$ $I. dsp^2$
$B. SF_6$ $II. sp^3d$
$C. Ni(CO)_4$ $III. sp^3d^2$
$D. [PtCl_4]^{2-}$ $IV. sp^3$
Choose the correct answer from the options given below $:$

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