By using Coulomb's law,define unit charge.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) In $SI$ units,the unit of charge is the Coulomb $(C)$.
According to Coulomb's law,the force between two point charges is given by $F = k \frac{q_1 q_2}{r^2}$,where $k = \frac{1}{4 \pi \epsilon_0} \approx 9 \times 10^9 \ N \cdot m^2/C^2$.
If we set $q_1 = q_2 = 1 \ C$ and $r = 1 \ m$,the force becomes $F = (9 \times 10^9) \times \frac{1 \times 1}{1^2} = 9 \times 10^9 \ N$.
Definition: $1 \ C$ is defined as the magnitude of charge that,when placed at a distance of $1 \ m$ from an identical charge in a vacuum,experiences an electrostatic repulsive force of $9 \times 10^9 \ N$.

Explore More

Similar Questions

The electrical force between two point charges is $200 \ N$. If we increase $10 \ \%$ charge on one of the charges and decrease $10 \ \%$ charge on the other,then the electrical force between them for the same distance becomes . . . . . . . . . . (in $N$)

What should be the equal charge on helium-filled balloons as shown in the figure?

Difficult
View Solution

In a right-angled triangle $ABC$,$AB = 3 \ cm$,$BC = 4 \ cm$,and $\angle ABC = \frac{\pi}{2}$. Charges of $+15 \ e.s.u.$,$+12 \ e.s.u.$,and $-20 \ e.s.u.$ are placed at $A$,$B$,and $C$ respectively. What is the net force on the charge at $B$ in $dynes$?

Two point charges $+6 \mu C$ and $+10 \mu C$ kept at a certain distance repel each other with a force of $30 \ N$. If each charge is given an additional charge of $-8 \mu C$,the two charges:

Why is the Coulombian force called a two-body force?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo