Complete the reaction: n + _{92}^{235}U to _{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a nuclear fission reaction, both the mass number and the atomic number must be conserved on both sides of the equation.Let the missing nucleus

Vedclass · Accepted Answer

$_{36}^{89}Kr$

Vedclass · Answer

(A) In a nuclear fission reaction, both the mass number and the atomic number must be conserved on both sides of the equation.Let the missing nucleus be $_{Z}^{A}X$.The reaction is: $_{0}^{1}n + _{92}^{235}U 	o _{56}^{144}Ba + _{Z}^{A}X + 3(_{0}^{1}n)$.Conservation of atomic number (charge): $0 + 92 = 56 + Z + 3(0) \implies 92 = 56 + Z \implies Z = 36$.The element with atomic number $36$ is Krypton $(Kr)$.Conservation of mass number: $1 + 235 = 144 + A + 3(1) \implies 236 = 147 + A \implies A = 89$.Therefore, the missing nucleus is $_{36}^{89}Kr$.

Complete the reaction: $n + _{92}^{235}U \to _{56}^{144}Ba + .... + 3n$

Similar Questions

$A$ neutron strikes a ${ }_{92}^{235}U$ nucleus and as a result ${ }_{38}^{93}Kr$ and ${ }_{56}^{140}Ba$ are produced along with:

$A$ nuclear reactor with $40\%$ efficiency produces $10^{14}$ fissions per second. Each fission releases $250 \text{ MeV}$ of energy. The power output of the reactor is ......... $W$.

The scientific principle that forms the basis of the Tokamak technology is

The nucleus of $_6C^{12}$ absorbs a neutron and emits a $\beta$-particle. The resulting nucleus is ........

If in a nuclear fission,a piece of uranium of mass $0.5\, g$ is lost,the energy obtained in $kWh$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module