Electric flux through a surface of area $100 \ m^2$ lying in the $xy$ plane is (in $V-m$) if $\vec E = \hat i + \sqrt 2 \hat j + \sqrt 3 \hat k$.

Gauss's law states that

An electric charge $q$ is placed at the centre of a cube of side $a$. The electric flux through one of its faces will be

Two equations are given below:
$A. \oint E \cdot dA = \frac{Q}{\varepsilon_0}$
$B. \oint B \cdot dA = 0$
They are:

An infinitely long wire has a uniform linear charge density $\lambda = 2 \ nC/m$. The net flux through a Gaussian cube of side length $a = \sqrt{3} \ cm$, if the wire passes through any two corners of the cube that are maximally displaced from each other, would be $x \ Nm^2 C^{-1}$, where $x$ is: [Neglect any edge effects and use $\frac{1}{4 \pi \varepsilon_0} = 9 \times 10^9 \ SI$ units] (in $\pi$)

$A$ closed surface passes through a spherical conductor as shown in the figure. If a negative charge $-Q$ is placed at point $P$,what will be the nature of the electric flux coming out of the closed surface?