કિંમત શોધો: sin frac{pi}{12} sin frac{2 pi}{1 | vedclass

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Question

(A) ધારો કે $P = \sin \frac{\pi}{12} \sin \frac{2 \pi}{12} \sin \frac{3 \pi}{12} \sin \frac{4 \pi}{12} \sin \frac{5 \pi}{12} \sin \frac{6 \pi}{12}$.કિ

Vedclass · Accepted Answer

$\frac{\sqrt{3}}{16 \sqrt{2}}$

Vedclass · Answer

(A) ધારો કે $P = \sin \frac{\pi}{12} \sin \frac{2 \pi}{12} \sin \frac{3 \pi}{12} \sin \frac{4 \pi}{12} \sin \frac{5 \pi}{12} \sin \frac{6 \pi}{12}$.કિંમતો મૂકતા:$\sin \frac{\pi}{12} = \frac{\sqrt{6}-\sqrt{2}}{4}$,$\sin \frac{2 \pi}{12} = \frac{1}{2}$,$\sin \frac{3 \pi}{12} = \frac{1}{\sqrt{2}}$,$\sin \frac{4 \pi}{12} = \frac{\sqrt{3}}{2}$,$\sin \frac{5 \pi}{12} = \frac{\sqrt{6}+\sqrt{2}}{4}$,$\sin \frac{6 \pi}{12} = 1$.તેથી,$P = \left( \frac{6-2}{16} ight) \left( \frac{\sqrt{3}}{4 \sqrt{2}} ight) = \frac{1}{4} 	imes \frac{\sqrt{3}}{4 \sqrt{2}} = \frac{\sqrt{3}}{16 \sqrt{2}}$.

કિંમત શોધો: $\sin \frac{\pi}{12} \sin \frac{2 \pi}{12} \sin \frac{3 \pi}{12} \sin \frac{4 \pi}{12} \sin \frac{5 \pi}{12} \sin \frac{6 \pi}{12}$

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