Match the reactions given in Column-$I$ with the appropriate reagents in Column-$II$.
| Column-$I$ (Reaction) | Column-$II$ (Reagent) |
| :--- | :--- |
| $(A)$ $2CH_3COOH \rightarrow (CH_3CO)_2O$ | $(i)$ $(I) NH_3, (II) \Delta, -H_2O$ |
| $(B)$ Phthalic acid $\rightarrow$ Phthalamide | $(ii)$ $(I) Br_2 / \text{red phosphorous}, (II) H_2O$ |
| $(C)$ $CH_3CH_2COOH \rightarrow CH_3CHBrCOOH$ | $(iii)$ $Br_2 / FeBr_3$ |
| $(D)$ Benzoic acid $\rightarrow$ $m$-Bromobenzoic acid | $(iv)$ $H^+, \Delta \text{ OR } P_2O_5, \Delta$ |

(A-IV, B-I, C-II, D-III) $(A)-(iv)$: Dehydration of acetic acid using $P_2O_5$ or $H^+, \Delta$ gives acetic anhydride.
$(B)-(i)$: Phthalic acid reacts with $NH_3$ followed by heating to form phthalamide.
$(C)-(ii)$: Hell-Volhard-Zelinsky reaction uses $Br_2 / \text{red phosphorous}$ followed by $H_2O$ to alpha-brominate carboxylic acids.
$(D)-(iii)$: Electrophilic aromatic substitution of benzoic acid (meta-directing group) with $Br_2 / FeBr_3$ gives $m$-bromobenzoic acid.
Therefore,the correct matching is $(A)-(iv), (B)-(i), (C)-(ii), (D)-(iii)$.