Given that $E$ and $F$ are events such that $P(E)=0.6$,$P(F)=0.3$,and $P(E \cap F)=0.2$,find $P(E|F)$ and $P(F|E)$.
- A$P(E|F) = \frac{2}{3}$ and $P(F|E) = \frac{1}{3}$
- B$P(E|F) = \frac{1}{3}$ and $P(F|E) = \frac{2}{3}$
- C$P(E|F) = \frac{1}{2}$ and $P(F|E) = \frac{1}{4}$
- D$P(E|F) = \frac{3}{2}$ and $P(F|E) = 3$
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