Heena can do a work in 20 days,while Himani c | vedclass

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(C) Efficiency of Heena $= 1/20$ of the work per day.Efficiency of Himani $= 1/25$ of the work per day.Since Heena and Himani worked for the entire $1

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$70$

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(C) Efficiency of Heena $= 1/20$ of the work per day.Efficiency of Himani $= 1/25$ of the work per day.Since Heena and Himani worked for the entire $10$ days,the work done by them is:Work done by Heena $= 10 	imes (1/20) = 1/2 = 50\%$ of the total work.Work done by Himani $= 10 	imes (1/25) = 10/25 = 2/5 = 40\%$ of the total work.Total work done by Heena and Himani $= 50\% + 40\% = 90\%$.Remaining work done by Mayuri $= 100\% - 90\% = 10\%$.Since wages are distributed based on the work done,Mayuri's share $= 10\%$ of $Rs. 700 = Rs. 70$.

Heena can do a work in $20$ days,while Himani can do the same work in $25$ days. They started the work jointly. $A$ few days later,Mayuri also joined them,and thus all of them completed the whole work in $10$ days. All of them were paid a total of $Rs. 700$. What is the share of Mayuri (in $Rs.$)?

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