If sqrt{7 sqrt{7 sqrt{7 sqrt{7 cdots}}}} = (3 | vedclass

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Question

(C) Let $x = \sqrt{7 \sqrt{7 \sqrt{7 \cdots}}}$.Squaring both sides,we get $x^2 = 7 \sqrt{7 \sqrt{7 \cdots}} = 7x$.Since $x 
eq 0$,we have $x = 7$.Gi

Vedclass · Accepted Answer

$\frac{4}{3}$

Vedclass · Answer

(C) Let $x = \sqrt{7 \sqrt{7 \sqrt{7 \cdots}}}$.Squaring both sides,we get $x^2 = 7 \sqrt{7 \sqrt{7 \cdots}} = 7x$.Since $x 
eq 0$,we have $x = 7$.Given the equation $(343)^{y-1} = 7$.We know that $343 = 7^3$,so $(7^3)^{y-1} = 7^1$.This simplifies to $7^{3(y-1)} = 7^1$.Equating the exponents,$3(y-1) = 1$.$3y - 3 = 1 \Rightarrow 3y = 4$.Therefore,$y = \frac{4}{3}$.

If $\sqrt{7 \sqrt{7 \sqrt{7 \sqrt{7 \cdots}}}} = (343)^{y-1}$,then $y$ is equal to

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