यदि $\tan A = \frac{1}{2}$ है,तो $\tan 3A = $

  • A
    $\frac{9}{2}$
  • B
    $\frac{11}{2}$
  • C
    $\frac{7}{2}$
  • D
    $-\frac{1}{2}$

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$\cos^2 \left( \frac{\pi}{6} + \theta \right) - \sin^2 \left( \frac{\pi}{6} - \theta \right) = $

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