If {T_0}, {T_1}, {T_2}, dots, {T_n} represent | vedclass

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(B) Let the expansion be $(x + a)^n = {T_0} + {T_1} + {T_2} + {T_3} + \dots + {T_n}$.Replacing $a$ with $ai$,we get $(x + ai)^n = ({T_0} - {T_2} + {T_

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$({x^2} + {a^2})^n$

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(B) Let the expansion be $(x + a)^n = {T_0} + {T_1} + {T_2} + {T_3} + \dots + {T_n}$.Replacing $a$ with $ai$,we get $(x + ai)^n = ({T_0} - {T_2} + {T_4} - \dots) + i({T_1} - {T_3} + {T_5} - \dots)$.Let $S_1 = ({T_0} - {T_2} + {T_4} - \dots)$ and $S_2 = ({T_1} - {T_3} + {T_5} - \dots)$.Then $(x + ai)^n = S_1 + iS_2$.Similarly,replacing $a$ with $-ai$,we get $(x - ai)^n = S_1 - iS_2$.Multiplying these two equations:$(x + ai)^n (x - ai)^n = (S_1 + iS_2)(S_1 - iS_2)$.$((x + ai)(x - ai))^n = S_1^2 + S_2^2$.$(x^2 - (ai)^2)^n = S_1^2 + S_2^2$.Since $i^2 = -1$,we have $(x^2 + a^2)^n = S_1^2 + S_2^2$.

If ${T_0}, {T_1}, {T_2}, \dots, {T_n}$ represent the terms in the expansion of ${(x + a)^n}$,then $({T_0} - {T_2} + {T_4} - \dots)^2 + ({T_1} - {T_3} + {T_5} - \dots)^2 = $

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