જો m tan (theta - 30^circ) = n tan (theta + 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) આપેલ છે કે,$m 	an (	heta - 30^\circ) = n 	an (	heta + 120^\circ)$.$\frac{m}{n} = \frac{	an (	heta + 120^\circ)}{	an (	heta - 30^\circ)}$.ય

Vedclass · Accepted Answer

$2 \cos 2	heta$

Vedclass · Answer

(A) આપેલ છે કે,$m 	an (	heta - 30^\circ) = n 	an (	heta + 120^\circ)$.$\frac{m}{n} = \frac{	an (	heta + 120^\circ)}{	an (	heta - 30^\circ)}$.યોગ-વિયોગની રીત (componendo and dividendo) વાપરતા:$\frac{m + n}{m - n} = \frac{	an (	heta + 120^\circ) + 	an (	heta - 30^\circ)}{	an (	heta + 120^\circ) - 	an (	heta - 30^\circ)}$.$\frac{m + n}{m - n} = \frac{\sin((	heta + 120^\circ) + (	heta - 30^\circ))}{\sin((	heta + 120^\circ) - (	heta - 30^\circ))} = \frac{\sin(2	heta + 90^\circ)}{\sin(150^\circ)}$.$\sin(2	heta + 90^\circ) = \cos 2	heta$ અને $\sin(150^\circ) = \frac{1}{2}$ હોવાથી:$\frac{m + n}{m - n} = \frac{\cos 2	heta}{1/2} = 2 \cos 2	heta$.

જો $m \tan (\theta - 30^\circ) = n \tan (\theta + 120^\circ)$ હોય,તો $\frac{m + n}{m - n} = $

Similar Questions

$\sin {163^\circ} \cos {347^\circ} + \sin {73^\circ} \sin {167^\circ} = $

$\cos ^2\left(\frac{\pi}{6}+\theta\right)-\sin ^2\left(\frac{\pi}{6}-\theta\right)$ ની કિંમત શોધો.

$\cos \alpha \sin (\beta - \gamma ) + \cos \beta \sin (\gamma - \alpha ) + \cos \gamma \sin (\alpha - \beta ) = $

જો $\theta \in \left(0, \frac{\pi}{2}\right)$ માટે $\tan 3\theta \cdot \tan 2\theta \cdot \tan \theta + \tan 2\theta + \tan \theta = 1$ હોય,તો $\theta =$

જો $\cos (\alpha + \beta) = \frac{3}{5}$,$\sin (\alpha - \beta) = \frac{5}{13}$ અને $0 < \alpha, \beta < \frac{\pi}{4}$ હોય,તો $\tan (2\alpha)$ ની કિંમત શોધો.

Vedclass Test Series

Exam Paper Generator

Online Exam Module