If |x+5| geq 10,then: | vedclass

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(C) Given the inequality $|x+5| \geq 10$. By the property of absolute value inequalities,$|u| \geq a$ implies $u \leq -a$ or $u \geq a$. Therefore,$x+

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$x \in (-\infty, -15] \cup [5, \infty)$

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(C) Given the inequality $|x+5| \geq 10$. By the property of absolute value inequalities,$|u| \geq a$ implies $u \leq -a$ or $u \geq a$. Therefore,$x+5 \leq -10$ or $x+5 \geq 10$. Solving the first part: $x \leq -10 - 5 \Rightarrow x \leq -15$. Solving the second part: $x \geq 10 - 5 \Rightarrow x \geq 5$. Combining these,we get $x \in (-\infty, -15] \cup [5, \infty)$.

If $|x+5| \geq 10$,then:

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