જો $\frac{x^2-3x+1}{(x-1)(x-2)(x-3)}=\frac{A}{x-3}+\frac{B}{(x-1)(x-2)}+\frac{C}{(x-1)(x-2)(x-3)}$ હોય,તો $B=$

  • A
    $0$
  • B
    $1$
  • C
    $-1$
  • D
    $2$

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$\begin{aligned} & \text{જો } \frac{4x^2+5x^4+7}{(x^2+1)(x^4+x^2+1)} = \frac{Ax+B}{x^2+1} \\ & + \frac{Cx^3+Dx^2+Ex+F}{x^4+x^2+1}, \text{ હોય તો } \\ & B+2(D+F+E)-C \cdot A = \end{aligned}$

$\frac{3x^3 - 8x^2 + 10}{(x - 1)^4}$ નું આંશિક અપૂર્ણાંક સ્વરૂપ શું છે?

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$\text{જો } \frac{3x^2+1}{(x^2+1)(x^2+2)^2} = \frac{Ax+B}{x^2+1} + \frac{Cx+D}{x^2+2} + \frac{Ex+F}{(x^2+2)^2} \text{ હોય, તો } A+C+E = $

જો $\frac{x+1}{x^4(x+2)}=\frac{A}{x}+\frac{B}{x^2}+\frac{C}{x^3}+\frac{D}{x^4}+\frac{E}{x+2}$ હોય, તો $B+D+E$ ની કિંમત શોધો.

$\frac{3x}{(x-2)(x-1)}$ ના વિસ્તરણમાં $x^4$ નો સહગુણક શોધવા માટે,જે અંતરાલમાં વિસ્તરણ માન્ય છે તે છે

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