જો $y = \cos^{-1}(\cos x)$ હોય,તો $x = \frac{5\pi}{4}$ આગળ $\frac{dy}{dx}$ શોધો.

  • A
    $1$
  • B
    $-1$
  • C
    $0$
  • D
    $\frac{1}{\sqrt{2}}$

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$\cot \left(\sum_{n=1}^{50} \tan ^{-1}\left(\frac{1}{1+n+n^2}\right)\right) = $

જો $y = \sec^{-1}\left( \frac{\sqrt{x} + 1}{\sqrt{x} - 1} \right) + \sin^{-1}\left( \frac{\sqrt{x} - 1}{\sqrt{x} + 1} \right)$ હોય,તો $\frac{dy}{dx} = $

$2{\tan ^{ - 1}}\left[ {\sqrt {\frac{{a - b}}{{a + b}}} \tan \frac{\theta }{2}} \right] = $

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ધારો કે $M$ અને $m$ એ અંતરાલ $[0, \frac{\pi}{2}]$ માં વિધેય $f(x) = \tan^{-1}(\sin x + \cos x)$ ની મહત્તમ અને ન્યૂનતમ કિંમતો છે. તો $\tan(M - m)$ ની કિંમત શોધો:

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