यदि $y = \frac{2(x - \sin x)^{3/2}}{\sqrt{x}}$ है,तो $\frac{dy}{dx} = $

  • A
    $\frac{2(x - \sin x)^{3/2}}{\sqrt{x}}\left[ \frac{3}{2} \cdot \frac{1 - \cos x}{1 - \sin x} - \frac{1}{2x} \right]$
  • B
    $\frac{2(x - \sin x)^{3/2}}{\sqrt{x}}\left[ \frac{3}{2} \cdot \frac{1 - \cos x}{x - \sin x} - \frac{1}{2x} \right]$
  • C
    $\frac{2(x - \sin x)^{1/2}}{\sqrt{x}}\left[ \frac{3}{2} \cdot \frac{1 - \cos x}{x - \sin x} - \frac{1}{2x} \right]$
  • D
    इनमें से कोई नहीं

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