જો $\frac{\sec 8\theta - 1}{\sec 4\theta - 1} = \frac{a + b \tan^2 2\theta}{1 + c \tan^2 2\theta + d \tan^4 2\theta}$ (જ્યાં $\theta \neq \frac{n\pi}{16}, n \in I$),તો $(a - b + c - d)$ ની કિંમત શોધો.

  • A
    $0$
  • B
    $1$
  • C
    $7$
  • D
    $13$

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Similar Questions

$\sqrt{2+\sqrt{2+\sqrt{2+2 \cos 8 \theta}}} = $

જો $\tan \alpha = \frac{-12}{5}$,$\cot \beta = \frac{7}{24}$,$\alpha$ બીજા ચરણમાં નથી અને $\beta$ પ્રથમ ચરણમાં નથી,તો $\sqrt{13} \sin \frac{\alpha}{2} + \cos \frac{\beta}{2} + \tan \frac{\alpha}{2} \cot \frac{\beta}{2} = $

જો $3 \sin 2 \theta = 2 \sin 3 \theta$ અને $0 < \theta < \pi$ હોય,તો $\sin \theta$ ની કિંમત કેટલી થાય?

જો $\sin x + \cos x = \frac{1}{5}$ હોય,તો $\tan 2x$ ની કિંમત શોધો.

$\tan \left( \frac{\pi }{4} + \theta \right) - \tan \left( \frac{\pi }{4} - \theta \right) = $

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