(C) For a quadratic equation $ax^2 + bx + c = 0$,the discriminant $D$ is given by $D = b^2 - 4ac$.Given the equation $kx^2 - 6x + 1 = 0$,we have $a =

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(C) For a quadratic equation $ax^2 + bx + c = 0$,the discriminant $D$ is given by $D = b^2 - 4ac$.Given the equation $kx^2 - 6x + 1 = 0$,we have $a = k$,$b = -6$,and $c = 1$.Since the discriminant is $0$,we set $D = 0$:$(-6)^2 - 4(k)(1) = 0$$36 - 4k = 0$$4k = 36$$k = 9$.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

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If the value of the discriminant of a quadratic equation $kx^2 - 6x + 1 = 0$ is $0$,then $k = \ldots$

A
$3$
B
$2$
C
$9$
D
$1$

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Mix Examples - Quadratic Equations

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If the value of the discriminant of a quadratic equation $kx^2 - 6x + 1 = 0$ is $0$,then $k = \ldots$

Similar Questions

Obtain the roots of the following quadratic equation by using the general formula for the solution: $2x^{2} - 2\sqrt{2}x + 1 = 0$.

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