In a common emitter (CE) amplifier having a v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Voltage gain is given by the product of current gain and resistance gain.$A_{v} = \beta 	imes \frac{R_{	ext{out}}}{R_{	ext{in}}}$Since transcon

Vedclass · Accepted Answer

$\frac{2}{3} G$

Vedclass · Answer

(D) Voltage gain is given by the product of current gain and resistance gain.$A_{v} = \beta 	imes \frac{R_{	ext{out}}}{R_{	ext{in}}}$Since transconductance $g_{m} = \frac{\beta}{R_{	ext{in}}}$,we can write $R_{	ext{in}} = \frac{\beta}{g_{m}}$.Substituting this into the voltage gain formula: $A_{v} = \beta 	imes \frac{R_{	ext{out}}}{\beta / g_{m}} = g_{m} R_{	ext{out}}$.For the first transistor: $G = 0.03 	imes R_{	ext{out}}$ (Equation $i$).For the second transistor: $G' = 0.02 	imes R_{	ext{out}}$ (Equation $ii$).Dividing Equation $ii$ by Equation $i$: $\frac{G'}{G} = \frac{0.02}{0.03} = \frac{2}{3}$.Therefore,the new voltage gain is $G' = \frac{2}{3} G$.

In a common emitter $(CE)$ amplifier having a voltage gain $G,$ the transistor used has transconductance $0.03\, mho$ and current gain $25.$ If the above transistor is replaced with another one with transconductance $0.02\, mho$ and current gain $20,$ the voltage gain will be

Similar Questions

The current amplification factor of a transistor in common emitter configuration is $80$. If the emitter current is $2.43 \text{ mA}$, then the base current is (in $\mu \text{A}$)

$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. What is the change in collector current?

When $n-p-n$ junction transistor is used as an amplifier in common emitter mode,

In a $p-n-p$ transistor working as a common base amplifier, when the current gain is $0.96$ and emitter current is $7.2 \,mA$, the base current is (in $\,mA$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module