In trapezium ABCD,AB || CD and AB = 2 , CD. I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In trapezium $ABCD$,since $AB || CD$,$\Delta AOB$ is similar to $\Delta COD$ by $AA$ similarity criterion ($\angle OAB = \angle OCD$ and $\angle O

Vedclass · Accepted Answer

$21$

Vedclass · Answer

(A) In trapezium $ABCD$,since $AB || CD$,$\Delta AOB$ is similar to $\Delta COD$ by $AA$ similarity criterion ($\angle OAB = \angle OCD$ and $\angle OBA = \angle ODC$ as alternate interior angles).The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.$\frac{	ext{Area}(\Delta AOB)}{	ext{Area}(\Delta COD)} = \left( \frac{AB}{CD} ight)^2$Given $AB = 2 \, CD$,so $\frac{AB}{CD} = 2$.$\frac{84}{	ext{Area}(\Delta COD)} = (2)^2 = 4$$	ext{Area}(\Delta COD) = \frac{84}{4} = 21 \, cm^2$.

In trapezium $ABCD$,$AB || CD$ and $AB = 2 \, CD$. Its diagonals intersect at $O$. If the area of $\Delta AOB = 84 \, cm^2$,then the area of $\Delta COD$ is equal to (in $cm^2$)

Similar Questions

The ratio of the area of a square to that of the square drawn on its diagonal is

$A$ rope,by which a horse is tied,is increased from $12 \ m$ to $23 \ m$. How much additional ground will it be able to graze? (in $m^2$)

$ABCD$ is a trapezium with $AD$ and $BC$ as parallel sides. $E$ is a point on $BC$. The ratio of the area of $ABCD$ to that of $\Delta AED$ is

The area of a triangular lawn is $1600 \, m^{2}$. If one side is $64 \, m$ long and the other two sides are equal in length,the length of each equal side is......$m$

The area of a triangle is $216 \, cm^{2}$ and its sides are in the ratio $3:4:5$. The perimeter of the triangle is ....... $cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module