ધારો કે $\frac{\pi}{2} < x < \pi$ એવું છે કે જેથી $\cot x = \frac{-5}{\sqrt{11}}$. તો $\left(\sin \frac{11x}{2}\right)(\sin 6x - \cos 6x) + \left(\cos \frac{11x}{2}\right)(\sin 6x + \cos 6x)$ ની કિંમત શોધો.
- A$\frac{\sqrt{11}-1}{2\sqrt{3}}$
- B$\frac{\sqrt{11}+1}{2\sqrt{3}}$
- C$\frac{\sqrt{11}+1}{3\sqrt{2}}$
- D$\frac{\sqrt{11}-1}{3\sqrt{2}}$
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