Note the frequency of two-wheelers, three-wheelers, and four-wheelers passing by your school gate during a specific time interval. Calculate the probability that any one vehicle chosen from the total vehicles observed is a two-wheeler.

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(N/A) To find the probability, follow these steps:
$1$. Let $n_1$ be the number of two-wheelers, $n_2$ be the number of three-wheelers, and $n_3$ be the number of four-wheelers observed.
$2$. Calculate the total number of vehicles observed: $N = n_1 + n_2 + n_3$.
$3$. The probability $P$ of selecting a two-wheeler is given by the ratio of the number of two-wheelers to the total number of vehicles.
$4$. Formula: $P(\text{two-wheeler}) = \frac{n_1}{N} = \frac{n_1}{n_1 + n_2 + n_3}$.

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An organisation selected $2400$ families at random and surveyed them to determine a relationship between income level and the number of vehicles in a family. The information gathered is listed in the table below:
Monthly income (in Rs.) / Vehicles per family $0$ $1$ $2$ Above $2$
Less than $7000$ $10$ $160$ $25$ $0$
$7000 - 10000$ $0$ $305$ $27$ $2$
$10000 - 13000$ $1$ $535$ $29$ $1$
$13000 - 16000$ $2$ $469$ $59$ $25$
$16000$ or more $1$ $579$ $82$ $88$

Suppose a family is chosen. Find the probability that the family chosen is:
$(i)$ Earning Rs. $10000 - 13000$ per month and owning exactly $2$ vehicles.
$(ii)$ Earning Rs. $16000$ or more per month and owning exactly $1$ vehicle.
$(iii)$ Earning less than Rs. $7000$ per month and does not own any vehicle.
$(iv)$ Earning Rs. $13000 - 16000$ per month and owning more than $2$ vehicles.
$(v)$ Owning not more than $1$ vehicle.

An insurance company selected $2000$ drivers at random in a particular city to find a relationship between age and accidents. The data obtained are given in the following table:
Age of drivers (in years) $0$ accidents $1$ accident $2$ accidents $3$ accidents Over $3$ accidents
$18-29$ $440$ $160$ $110$ $61$ $35$
$30-50$ $505$ $125$ $60$ $22$ $18$
Above $50$ $360$ $45$ $35$ $15$ $9$

Find the probabilities of the following events for a driver chosen at random from the city:
$(i)$ Being $18-29$ years of age and having exactly $3$ accidents in one year.
$(ii)$ Being $30-50$ years of age and having one or more accidents in a year.
$(iii)$ Having no accidents in one year.

The following frequency distribution table shows the blood groups of $30$ students of a class. Use this table to determine the probability that a student of this class,selected at random,has blood group $AB$.
Blood group Number of students
$A$ $9$
$B$ $6$
$AB$ $3$
$O$ $12$
Total $30$

Consider the frequency distribution table which gives the weights of $38$ students of a class.
Weights (in $kg$) Number of students
$31-35$ $9$
$36-40$ $5$
$41-45$ $14$
$46-50$ $3$
$51-55$ $1$
$56-60$ $2$
$61-65$ $2$
$66-70$ $1$
$71-75$ $1$
Total $38$

$(i)$ Find the probability that the weight of a student in the class lies in the interval $46-50 \, kg$.
$(ii)$ Give two events in this context,one having probability $0$ and the other having probability $1$.

$A$ teacher wanted to analyze the performance of two sections of students in a mathematics test of $100$ marks. Looking at their performances,she found that a few students got under $20$ marks and a few got $70$ marks or above. So she decided to group them into intervals of varying sizes as follows: $0-20, 20-30, ..., 60-70, 70-100$. Then she formed the following table:
Marks Number of students
$0-20$ $7$
$20-30$ $10$
$30-40$ $10$
$40-50$ $20$
$50-60$ $20$
$60-70$ $15$
$70$ and above $8$
Total $90$

$(i)$ Find the probability that a student obtained less than $20\%$ in the mathematics test.
$(ii)$ Find the probability that a student obtained marks $60$ or above.

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