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(B) In an $L-C-R$ series circuit,the power delivered by the source is given by $P = I^2 R = \frac{V^2 R}{Z^2}$.Here,$Z = \sqrt{R^2 + (X_L - X_C)^2}$ i

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$\omega L = \frac{1}{\omega C}$

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(B) In an $L-C-R$ series circuit,the power delivered by the source is given by $P = I^2 R = \frac{V^2 R}{Z^2}$.Here,$Z = \sqrt{R^2 + (X_L - X_C)^2}$ is the impedance of the circuit.For the power to be maximum,the impedance $Z$ must be minimum.$Z$ is minimum when the reactance part $(X_L - X_C)$ becomes zero.This condition is known as resonance,where $X_L = X_C$.Since $X_L = \omega L$ and $X_C = \frac{1}{\omega C}$,the condition for maximum power is $\omega L = \frac{1}{\omega C}$.

Power delivered by the source of the circuit becomes maximum,when

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