Solid Ba(NO_3)_2 is gradually dissolved in a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The dissolution of $Na_2CO_3$ in water is given by: $Na_2CO_3 ightarrow 2Na^{+} + CO_3^{2-}$.Given the concentration of $Na_2CO_3$ is $1.0 	ime

Vedclass · Accepted Answer

$5.1 	imes 10^{-5} \ M$

Vedclass · Answer

(A) The dissolution of $Na_2CO_3$ in water is given by: $Na_2CO_3 ightarrow 2Na^{+} + CO_3^{2-}$.Given the concentration of $Na_2CO_3$ is $1.0 	imes 10^{-4} \ M$,the concentration of carbonate ions is $[CO_3^{2-}] = 1.0 	imes 10^{-4} \ M$.For the precipitation of $BaCO_3$ to begin,the ionic product must exceed the solubility product constant $(K_{sp})$.The condition for the start of precipitation is: $[Ba^{2+}][CO_3^{2-}] = K_{sp}(BaCO_3)$.Substituting the given values: $[Ba^{2+}] 	imes (1.0 	imes 10^{-4}) = 5.1 	imes 10^{-9}$.Solving for $[Ba^{2+}]$: $[Ba^{2+}] = \frac{5.1 	imes 10^{-9}}{1.0 	imes 10^{-4}} = 5.1 	imes 10^{-5} \ M$.

Solid $Ba(NO_3)_2$ is gradually dissolved in a $1.0 \times 10^{-4} \ M$ $Na_2CO_3$ solution. At what concentration of $Ba^{2+}$ will a precipitate begin to form? ($K_{sp}$ for $BaCO_3 = 5.1 \times 10^{-9}$)

Similar Questions

Solubility of calcium phosphate (molecular mass,$M$) in water is $W \ g$ per $100 \ mL$ at $25^{\circ} C$. Its solubility product at $25^{\circ} C$ will be approximately.

When equal volumes of $Ca^{2+}$ and $F^{-}$ solutions are mixed,in which of the solutions precipitation will not occur? $(K_{sp} \text{ of } CaF_2 = 1.6 \times 10^{-10})$

The compound not soluble in acetic acid is

Solubility of $CaF_2$ in a solution of $Ca(NO_3)_2$ will be represented by the concentration term?

The solubility of $Ca_3(PO_4)_2$ in water is $y \text{ moles/litre}$. Its solubility product is

Vedclass Test Series

Exam Paper Generator

Online Exam Module