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(D) For equation $I$: $4x^2 - 29x + 45 = 0$Using the splitting the middle term method: $4x^2 - 20x - 9x + 45 = 0$$4x(x - 5) - 9(x - 5) = 0$$(4x - 9)(x

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if $x = y$ or the relationship between $x$ and $y$ cannot be established.

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(D) For equation $I$: $4x^2 - 29x + 45 = 0$Using the splitting the middle term method: $4x^2 - 20x - 9x + 45 = 0$$4x(x - 5) - 9(x - 5) = 0$$(4x - 9)(x - 5) = 0$So,$x = 5$ or $x = 9/4 = 2.25$.For equation $II$: $3y^2 - 19y + 28 = 0$Using the splitting the middle term method: $3y^2 - 12y - 7y + 28 = 0$$3y(y - 4) - 7(y - 4) = 0$$(3y - 7)(y - 4) = 0$So,$y = 4$ or $y = 7/3 \approx 2.33$.Comparing the values:If $x = 5$,then $x > y$ (since $y$ is $4$ or $2.33$).If $x = 2.25$,then $x Since we get different results ($x > y$ and $x < y$),the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and provide the correct answer from the given options.
$I.$ $4x^2 - 29x + 45 = 0$
$II.$ $3y^2 - 19y + 28 = 0$

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Solve the given two equations and provide the correct answer from the given options.$I.$ $4x^2 - 29x + 45 = 0$$II.$ $3y^2 - 19y + 28 = 0$