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(C) Let $M_e$ and $R_e$ be the mass and radius of the earth, and $M_m$ and $R_m$ be the mass and radius of the moon. Let $D$ be the distance between t

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$C$

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(C) Let $M_e$ and $R_e$ be the mass and radius of the earth, and $M_m$ and $R_m$ be the mass and radius of the moon. Let $D$ be the distance between the centers of the earth and the moon.If the spaceship is at a distance $x$ from the center of the earth, the net gravitational force $F$ on the passenger of mass $M$ is given by $F = \frac{G M_e M}{x^2} - \frac{G M_m M}{(D-x)^2}$.Since the spaceship moves with constant velocity $v$, $x = vt$. Thus, $F(t) = G M \left( \frac{M_e}{(vt)^2} - \frac{M_m}{(D-vt)^2} \right)$.At $t=0$ (on Earth's surface), $F = Mg$. At $t=t_m$ (on Moon's surface), $F = Mg'$.Between the Earth and the Moon, there exists a point (neutral point) where the gravitational pull of the Earth and the Moon cancel each other out, meaning $F=0$. This occurs at some time $t$ between $0$ and $t_m$.Curve $C$ is the only one that shows the force decreasing from $Mg$, reaching zero at the neutral point, and then increasing to $Mg'$ at the moon's surface.

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