The H.C.F. and L.C.M. of two numbers are 44 a | vedclass

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(C) We know that for any two numbers,the product of the numbers is equal to the product of their $H.C.F.$ and $L.C.M.$Let the two numbers be $x$ and $

Vedclass · Accepted Answer

$132$

Vedclass · Answer

(C) We know that for any two numbers,the product of the numbers is equal to the product of their $H.C.F.$ and $L.C.M.$Let the two numbers be $x$ and $y.$Given: $H.C.F. = 44$,$L.C.M. = 264.$According to the problem,the first number $x$ divided by $2$ gives a quotient of $44.$So,$x / 2 = 44 \implies x = 44 	imes 2 = 88.$Using the formula: $x 	imes y = H.C.F. 	imes L.C.M.$$88 	imes y = 44 	imes 264.$$y = (44 	imes 264) / 88.$$y = 264 / 2 = 132.$Therefore,the other number is $132$.

The $H.C.F.$ and $L.C.M.$ of two numbers are $44$ and $264,$ respectively. If the first number is divided by $2,$ the quotient is $44.$ The other number is

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