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(B) The side length of the square $ABCD$ is $28 \ cm$.Area of the square $= 	ext{side} 	imes 	ext{side} = 28 	imes 28 = 784 \ cm^2$.Since there ar

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$168$

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(B) The side length of the square $ABCD$ is $28 \ cm$.Area of the square $= 	ext{side} 	imes 	ext{side} = 28 	imes 28 = 784 \ cm^2$.Since there are four identical circles inscribed in the square,the diameter of each circle is half the side of the square.Diameter of each circle $= 28 / 2 = 14 \ cm$.Radius of each circle $(r) = 14 / 2 = 7 \ cm$.Area of one circle $= \pi r^2 = (22 / 7) 	imes 7 	imes 7 = 154 \ cm^2$.Area of four such circles $= 4 	imes 154 = 616 \ cm^2$.Area of the shaded region $= 	ext{Area of square} - 	ext{Area of four circles} = 784 - 616 = 168 \ cm^2$.

The area of the shaded region within the square $ABCD$ is . . . . . . $cm^2$. (Assume the side of the square is $28 \ cm$ and it contains four identical circles).

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