The density of water is 1000 ; kg ; m^{-3}. T | vedclass

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(A) The density of liquid water is $\rho_{liquid} = 1000 \; kg \; m^{-3}$.The density of water vapour is $\rho_{vapour} = 0.6 \; kg \; m^{-3}$.Assumin

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$6 	imes 10^{-4}$

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(A) The density of liquid water is $ho_{liquid} = 1000 \; kg \; m^{-3}$.The density of water vapour is $ho_{vapour} = 0.6 \; kg \; m^{-3}$.Assuming the density of the water molecule itself is approximately equal to the density of liquid water,the molecular volume $V_{mol}$ for a given mass $M$ is $V_{mol} = M / ho_{liquid}$.The total volume occupied by the same mass $M$ in the vapour state is $V_{vapour} = M / ho_{vapour}$.The ratio of the molecular volume to the total volume is given by:$	ext{Ratio} = \frac{V_{mol}}{V_{vapour}} = \frac{M / ho_{liquid}}{M / ho_{vapour}} = \frac{ho_{vapour}}{ho_{liquid}}$.Substituting the given values:$	ext{Ratio} = \frac{0.6}{1000} = 0.6 	imes 10^{-3} = 6 	imes 10^{-4}$.

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