The diameter and altitude of a right circular cone,at a certain instant,were found to be $10 \ cm$ and $20 \ cm$ respectively. If its diameter is increasing at a rate of $2 \ cm/s$,then at what rate must its altitude change,in order to keep its volume constant (in $cm/s$)?

If the distance $s$ travelled by a particle in time $t$ is given by $s=t^2-2t+5$,then its acceleration is

$A$ particle moves in a straight line such that $s = \sqrt{t}$,then its acceleration is proportional to

If $s=60 t-5 t^2$ denotes the distance covered by a particle in time $t$,then the distance it covers before coming to rest is.... units.

$A$ particle starts moving from rest from a fixed point in a fixed direction. The distance $s$ from the fixed point at a time $t$ is given by $s = t^{2} + at - b + 17$, where $a$ and $b$ are real numbers. If the particle comes to rest after $5 \ s$ at a distance of $s = 25$ units from the fixed point, then the values of $a$ and $b$ are respectively:

Find the rate of change of the area of a circle with respect to its radius $r$ when $r=5 \text{ cm}$.