The electron in a hydrogen atom,upon absorbin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by $E_n = -\frac{13.6 \ eV}{n^2}$.For the ground state $(n_1 = 1)$,the

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) The energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by $E_n = -\frac{13.6 \ eV}{n^2}$.For the ground state $(n_1 = 1)$,the energy is $E_1 = -13.6 \ eV$.When the electron absorbs energy $\Delta E = 12.75 \ eV$,it jumps to a higher orbit $n_2$.The energy of the final state is $E_{n_2} = E_1 + \Delta E = -13.6 + 12.75 = -0.85 \ eV$.Using the formula $E_{n_2} = -\frac{13.6}{n_2^2}$,we get:$-0.85 = -\frac{13.6}{n_2^2}$$n_2^2 = \frac{13.6}{0.85} = 16$$n_2 = 4$.Therefore,the electron jumps to the $4^{th}$ orbit.

The electron in a hydrogen atom,upon absorbing $12.75 \ eV$ of energy,will jump to the ....... orbit.

Similar Questions

If an electron in a hydrogen atom undergoes a transition from the $4^{th}$ stationary orbit and emits a line in the Lyman series,calculate the wavelength of the emitted radiation.

The electron energy in a hydrogen atom is given by $E_n = (-2.18 \times 10^{-18})/n^2 \ J$. Calculate the energy required to remove an electron completely from the $n = 2$ orbit. What is the longest wavelength of light in $cm$ that can be used to cause this transition?

The figure shows six spectral lines in an emission spectrum arising from energy level transitions. Which of the following spectral lines does not appear in the absorption spectrum?

Explain the energy of a photon,the kinetic energy of an ejected electron,and the number of photons in the photoelectric effect.

Give names of atomic models and write about Thomson model.

Vedclass Test Series

Exam Paper Generator

Online Exam Module