The function $f: R \rightarrow R$ defined by $f(x) = e^x + e^{-x}$ is

  • A
    one-one
  • B
    onto
  • C
    bijective
  • D
    not bijective

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Similar Questions

Let $R$ denote the set of all real numbers and $R^{+}$ denote the set of all positive real numbers. For the subsets $A$ and $B$ of $R$,define $f: A \rightarrow B$ by $f(x) = x^2$ for $x \in A$. Match the items in Column-$I$ with the items in Column-$II$.
Column-$I$Column-$II$
$A$. $f$ is one-one and onto,if$1$. $A = R^{+}, B = R$
$B$. $f$ is one-one but not onto,if$2$. $A = B = R$
$C$. $f$ is onto but not one-one,if$3$. $A = R, B = R^{+}$
$D$. $f$ is neither one-one nor onto,if$4$. $A = B = R^{+}$

$A$ function from $A = \{x : -1 \leq x \leq 1\}$ to itself which is not a bijection is

Statement-$I$: Let $f : R \rightarrow R$ be a function such that $f(x) = x^3 + x^2 + 3x + \sin x$. Then $f$ is a one-one function.
Statement-$II$: $f(x)$ is a decreasing function.

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If $n(A) = 5$ and $n(B) = 8$,how many possible functions can be defined from $A$ to $B$?

If a real-valued function $f$ is defined by $f(x) = \frac{ax + \sqrt{a^2 - x^2}}{bx}$,then $f$ is

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