The mass defect in a particular nuclear react | vedclass

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Question

(D) Given mass defect $\Delta m = 0.3\, g = 0.3 	imes 10^{-3}\, kg$.Velocity of light $c = 3 	imes 10^8\, m/s$.Using Einstein's mass-energy equivale

Vedclass · Accepted Answer

$7.5 	imes 10^6$

Vedclass · Answer

(D) Given mass defect $\Delta m = 0.3\, g = 0.3 	imes 10^{-3}\, kg$.Velocity of light $c = 3 	imes 10^8\, m/s$.Using Einstein's mass-energy equivalence formula,$E = \Delta m c^2$.$E = (0.3 	imes 10^{-3}) 	imes (3 	imes 10^8)^2$.$E = 0.3 	imes 10^{-3} 	imes 9 	imes 10^{16} = 2.7 	imes 10^{13}\, J$.To convert Joules to kilowatt-hours $(kWh)$,we divide by $3.6 	imes 10^6\, J/kWh$.$E = \frac{2.7 	imes 10^{13}}{3.6 	imes 10^6} = 0.75 	imes 10^7 = 7.5 	imes 10^6\, kWh$.

The mass defect in a particular nuclear reaction is $0.3\, g$. The amount of energy liberated in kilowatt-hours $(kWh)$ is (Velocity of light = $3 \times 10^8\, m/s$)

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