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(C) The kinetic energy gained by an electron accelerated through a potential difference $V$ is given by $K = eV$.When this electron strikes the target

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$\frac{hc}{eV}$

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(C) The kinetic energy gained by an electron accelerated through a potential difference $V$ is given by $K = eV$.When this electron strikes the target,it produces $X$-rays. The maximum energy of the emitted $X$-ray photon corresponds to the case where the entire kinetic energy of the electron is converted into a single photon.Thus,$E_{max} = h
u_{max} = \frac{hc}{\lambda_{min}} = eV$.Rearranging this equation for the minimum wavelength,we get $\lambda_{min} = \frac{hc}{eV}$.

The minimum wavelength of $X$-rays produced by electrons accelerated by a potential difference of $V$ volts is equal to:

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