The oxidation state of Cr in CrO_5 is | vedclass

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Question

(D) The structure of $CrO_5$ is a butterfly structure where one oxygen atom is bonded to $Cr$ via a double bond (oxidation state $-2$) and four oxygen

Vedclass · Accepted Answer

$6$

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(D) The structure of $CrO_5$ is a butterfly structure where one oxygen atom is bonded to $Cr$ via a double bond (oxidation state $-2$) and four oxygen atoms are bonded via single bonds forming two peroxide linkages (each oxygen atom has an oxidation state of $-1$).Let the oxidation state of $Cr$ be $x$.The sum of oxidation states in a neutral molecule is zero.$x + 1(-2) + 4(-1) = 0$$x - 2 - 4 = 0$$x - 6 = 0$$x = +6$

The oxidation state of $Cr$ in $CrO_5$ is

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