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(D) The magnetic flux $\phi$ linked with a coil is given by the formula $\phi = N \vec{B} \cdot \vec{A} = N B A \cos 	heta$,where $	heta$ is the ang

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(D) The magnetic flux $\phi$ linked with a coil is given by the formula $\phi = N \vec{B} \cdot \vec{A} = N B A \cos 	heta$,where $	heta$ is the angle between the magnetic field vector $\vec{B}$ and the area vector $\vec{A}$.The area vector $\vec{A}$ is always perpendicular to the plane of the coil.Given that the plane of the coil is parallel to the magnetic field $\vec{B}$,the angle between the area vector $\vec{A}$ and the magnetic field $\vec{B}$ is $90^\circ$.Therefore,$	heta = 90^\circ$.Substituting this into the formula: $\phi = N B A \cos(90^\circ) = N B A (0) = 0$.Thus,the magnetic flux linked with the coil is zero.

The radius of a coil of $N$ turns is $R$. If the plane of the coil is placed parallel to a uniform magnetic field $B$,then the flux linked with the coil is:

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