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(C) For a common emitter $(CE)$ configuration of a transistor:Given: Voltage gain $(A_v)$ = $150$, Current gain $(\beta)$ = $50$, Base resistance $(R_

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$2550$

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(C) For a common emitter $(CE)$ configuration of a transistor:Given: Voltage gain $(A_v)$ = $150$, Current gain $(\beta)$ = $50$, Base resistance $(R_B)$ = $850 \Omega$.The formula for voltage gain in a $CE$ amplifier is given by:$A_v = \beta 	imes \left( \frac{R_C}{R_B} ight)$Substituting the given values into the formula:$150 = 50 	imes \left( \frac{R_C}{850} ight)$Rearranging to solve for collector resistance $(R_C)$:$\frac{R_C}{850} = \frac{150}{50}$$\frac{R_C}{850} = 3$$R_C = 3 	imes 850 = 2550 \Omega$Therefore, the resistance in the collector circuit is $2550 \Omega$.

The voltage gain and current gain of a transistor amplifier in common emitter configuration are respectively $150$ and $50$. If the resistance in the base circuit is $850 \Omega$, then the resistance in the collector circuit is: (in $\Omega$)

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